If the larger root of equation $x^2+\left(2-a^2\right)x+\left(1-a^2\right)=0$ is less than both the roots of the equation $x^2-\left(a^2+4a+1\right)x+a^2+4a=0$, then  the range of a, is

The roots of first equation are –1 and a2 –1. Now the roots of second equation are $1,a^2+4a$

According to given condition $a^2-1<1and{a}^2-1<a^2+4a$

$\begin{array}{l}a\in \left(-\sqrt{2},\sqrt{2}\right)anda>-\frac{1}{4}\\ \Rightarrow a\in \left(-\frac{1}{4},\sqrt{2}\right)\end{array}$