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Q.

If the LCM of $(x - a)$ and $(x - b)$ is $x^{2} - 2 x + 1$ , then the values of $a$ and $b$ are

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a

$- 2, 1$

b

1, 1

c

1, 2

d

$- 1, - 2$

answer is C.

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Detailed Solution

$x^{2} - 2 x + 1 = {(x - 1)}^{2} = (x - 1) (x - 1)$

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