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Q.

If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s, then the frequency for the second note is 

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a

55 Hz

b

110 Hz

c

165 Hz

d

220 Hz

answer is B.

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Detailed Solution

For closed pipe second note = 3v4l=3×3304×1.5=165Hz.

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