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Q.

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s, then the frequency for the second note is 

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a

4×3304Hz

b

3×3304Hz

c

2×3304Hz

d

2×4330Hz

answer is B.

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Detailed Solution

For closed pipe n1=v4l=3304Hz
Second note = 3n1=3×3004Hz

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If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s, then the frequency for the second note is