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If the length of a seconds pendulum is increased by 2% then in a day the pendulum

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loses 764 s

loses 964 s

gains 764 s

loses 864 s

answer is D.

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Detailed Solution

loss or gain of time per second is $\frac{T_{2} - T_{1}}{T_{1}} = \frac{\sqrt{l_{2}} - \sqrt{l_{1}}}{\sqrt{l_{1}}}$

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