If the letters of the word 'AJANTA' are permutated in all possible ways and the words thus formed are arranged in dictionary order. Find the rank of JANATA'.

The order of letters is A, A, A, J, N, T 
The number of words which begin with $A=\frac{5!}{2!}=60$ 
The number of words which begin with JAA = 3! =6 
The number of words which begin with JANAA = 1 
The next word is JANATA 
Rank= 60 +6 + 1 +1 = 68