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Q.

If the lines 3x-4y-7=0and 2x-3y-5=0 are two diameters of a circle of area 49π sq. units then equation of circle is

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a

x2+y2+2x−2y−62=0

b

x2+y2-2x+2y−62=0

c

x2+y2+2x−2y−47=0

d

x2+y2-2x+2y−47=0

answer is A.

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Detailed Solution

Solving diameters

C=(-1, 1) πr2=49π r2=49 (x+1)2+(y-1)2=49

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