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Q.

If the mass of a proton, mp= 1.008u, mass of neutron mn =1.009u, then the binding energy of an α  -particle of mass 4.003 u will be …. ×107 eV. (Round off to nearest integer)

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answer is 3.

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Detailed Solution

Mass defect,   ΔM=[Z.mp+(A−Z)mn]−M
 ΔM=[2x1.008+2x1.009]−4.003 ΔM=0.031u
 Binding Energy   Eb=ΔMx931.5MeV
    =28.87 MeV
    =29MeV
 

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