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Q.

If the mass of earth were 2 times the present mass, the mass of the moon were half the present mass and the moon were revolving round the earth at the same present distance, the time period of revolution of the moon would be (in days)

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a

56

b

28

c

$14 \sqrt{2}$

d

7

answer is C.

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Detailed Solution

From Kepler’s 3rd law, $T = 2 π \sqrt{\frac{r^{3}}{GM}}$

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If the mass of earth were 2 times the present mass, the mass of the moon were half the present mass and the moon were revolving round the earth at the same present distance, the time period of revolution of the moon would be (in days)