If the mass of the moon is $7.4 \times {10}^{22}\mathit{ kg}$, & the radius of the moon is $1.74 \times {10}^6\mathit{ m}$. Then the acceleration due to gravity on the surface on the moon is

The acceleration due to gravity on the surface of the moon is $1.63 \mathrm{m}/{\mathrm{s}}^2$
Given:
Mass of the moon, $\mathrm{m}=7.4\mathrm{ }\times \mathrm{ }{10}^{22} \mathrm{kg}$
The radius of the moon, $\mathrm{R}=1.74\mathrm{ }\times \mathrm{ }{10}^6 \mathrm{m}$
Gravitational constant, $\mathrm{G}=6.67\mathrm{ }\times \mathrm{ }{10}^{-11} \mathrm{N} {\mathrm{m}}^2/{\mathrm{kg}}^2$
We know, acceleration due to gravity,
$\mathrm{g} =\mathrm{ }\frac{\mathrm{G} \times \mathrm{m}}{{\mathrm{R}}^2}$
Putting the values of G, m and R in the above equation, we get
$\mathrm{g} =\mathrm{ }\frac{6.67\mathrm{ }\times \mathrm{ }{10}^{-11}\mathrm{ }\times \mathrm{ }7.4\mathrm{ }\times \mathrm{ }{10}^{22}}{{(1.74\mathrm{ }\times \mathrm{ }{10}^6\mathrm{ })}^2}$
$\mathrm{g} =\mathrm{ }1.63 \mathrm{m}/{\mathrm{s}}^2$