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If the maximum intensity of radiation for a black body is found at $2.65 μ m$ , the temperature of the radiating body is (Wien’s constant = $2.9 \times 10^{- 3} m K$ )

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927 K

1094 K

2173 K

2027 K

answer is B.

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Detailed Solution

$\begin{array}{l} λ_{\max} = \frac{b}{T} \\ T = \frac{2.9 \times 10^{- 3}}{2.65 \times 10^{- 6}} \\ T = 1094 k \end{array}$

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