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Q.

If the minimum value of the quadratic expression x2+5x2   is M and it exists at ‘a’ then Ma=  

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a

335

b

3.3

c

2.5

d

– 0.25

answer is A.

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Detailed Solution

Minimum at  x=b2a=52     M=(52)2+5(52)2=334Ma=3.3
 
 

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