If the moment of inertia of a disc about an axis tangential in its plane be I, then what will be the moment of inertia about the axis tangential but perpendicular to its plane?

The moment of inertia of the disc about an axis parallel to its plane is

$I_t=I_d+M{R}^2$$\Rightarrow I=\frac{1}{4}M{R}^2+M{R}^2$$=\frac{5}{4}M{R}^2$     or     $M{R}^2=\frac{4I}{5}$

Now, moment of inertia about a tangent perpendicular to its plane is

$I^{|}=\frac{3}{2}M{R}^2=\frac{3}{2}\times \frac{4}{5}I=\frac{6}{5}I$