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If the momentum of a body decreases by $30 %$ , its kinetic energy decreases by

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$60 %$

$69 %$

$51 %$

$90 %$

answer is B.

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Detailed Solution

$K = \frac{P^{2}}{2 m}$

$K_{1} = \frac{P^{2}}{2 m}$

$K_{2} = \frac{{(0.7 P)}^{2}}{2 m} = \frac{0.49 P^{2}}{2 m} = 0.49 K_{1}$

$\Rightarrow \frac{∆ K}{K_{1}} = 0.51 = 51 %$

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