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If the nitrogen tom has electronic configuration $1 s^{7}$ m it would have energy lower than that of the normal ground state configuration $1 s^{2} 2 s^{2} 2 p^{3}$ , because the electrons would be closer to the nucleus. Yet $1 s^{7}$ is not observed because it violates

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An Intiative by Sri Chaitanya

Pauli’s exclusion principle

Hund’s rule

Heisenberg uncertainty principle

Bohr postulates of stationary orbitals

answer is C.

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Detailed Solution

As maximum number of electrons in any orbit, sub-orbit or orbital is decided by Pauli’s law.

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