If the normal drawn from the origin to the straight line 2x + 7y = 6 = 0 makes angle $\theta withthepositivex-axis,then\theta =$

Given line  2x + 7y = 6

Let the equation of Normal is 7x-2y+k=0

It passes through (0,  0)

$\begin{array}{l}\Rightarrow 0-0+k=0\Rightarrow k=0\\ \therefore EquationofNormalis7x-2y=0\\ Slope=\frac{-7}{-2}=\frac{7}{2}\\ \therefore \mathrm{Tan}\theta =\frac{7}{2}\\ \theta ={\mathrm{Tan}}^{-1}\left(\frac{7}{2}\right)\end{array}$