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Q.

If the number exceeds 23 of itself by 7, then determine the number.


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a

21

b

44

c

2

d

7  

answer is A.

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Detailed Solution

Given, the number exceeds 23 of itself by 7.
Let x be the required number.
⇒ 2x3=x-7
On simplifying, we get,
⇒x=21 Hence, the correct option is 1.
 
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