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If the objective function for an L.P.P. is $Z = 3 x + 4 y$ and the comer points for unbounded feasible region are (9, 0), (4, 3), (2, 5) and (0, 8), then the minimum value of Z occurs at

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(0, 8)

(2, 5)

(4, 3)

(9, 0)

answer is C.

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Detailed Solution

$Z = 3 x + 4 y$

At $(9, 0), Z = 3 \times 9 + 4 \times 0 = 27$

At $(4, 3), Z = 3 \times 4 + 4 \times 3 = 24 \to$ Minimum

At $(2, 5), Z = 3 \times 2 + 4 \times 5 = 26$

At $(0, 8), Z = 3 \times 0 + 4 \times 8 = 32$ .

Hence, minimum of Z occurs at (4, 3).

$∴$ Option (c) is the correct answer.

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