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If the parabolas $y^{2} = α x;$ $25 ({(x - 3)}^{2} + {(y + 2)}^{2}) = {(3 x - 4 y - 2)}^{2}$ are equal then $α =$

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answer is B.

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Detailed Solution

Here $λ = 2.$ distance between $(3, - 2)$ to $3 x - 4 y - 2 = 0$
$= 2 \frac{| 9 + 8 - 2 |}{\sqrt{9 + 16}}$
$= \frac{2 (15)}{5}$
$= 2 (3)$
$= 6$

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