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If the particle is moving along a straight line given by the relation $s = 2 - 3 t + 4 t^{3}$ where s is in cms.., and t in sec. Its average velocity during the third sec is

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85 cm/s

90 cm/s

80 cm/s

73 cm/s

answer is A.

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Detailed Solution

s = 2 - 3 t + 4 t^{3}

$s (2) = 2 - 3 (2) + 4 {(2)}^{3} = 28 cm$

$s (3) = 2 - 3 (3) + 4 {(3)}^{3} = 101 cm$

$s_{3} = s (3) - s (2)$

$= 101 - 28$

$= 73 cm$

$t = 1sec$

$v_{avg} = \frac{s_{3}}{t} = \frac{73}{1}$

$v_{avg} = 73 cm/s$

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