Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

If the particle is moving along a straight line given by the relation $s = 2 - 3 t + 4 t^{3}$ where s is in cms.., and t in sec. Its average velocity during the third sec is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

85 cm/s

90 cm/s

80 cm/s

73 cm/s

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

s = 2 - 3 t + 4 t^{3}

$s (2) = 2 - 3 (2) + 4 {(2)}^{3} = 28 cm$

$s (3) = 2 - 3 (3) + 4 {(3)}^{3} = 101 cm$

$s_{3} = s (3) - s (2)$

$= 101 - 28$

$= 73 cm$

$t = 1sec$

$v_{avg} = \frac{s_{3}}{t} = \frac{73}{1}$

$v_{avg} = 73 cm/s$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test