If the particle is moving along a straight line given by the relation x = 2 - 3t +4t3 where s is in cm, and t in sec. Its average velocity during the third sec is

x=2−3t+4t3t=2⇒x2=2−6+32=28t=3⇒x3=2−9+108=101vavg =x3−x23−2=101−281=73cm/s

If the particle is moving along a straight line given by the relation x = 2 - 3t +4t3 where s is in cm, and t in sec. Its average velocity during the third sec is

x=2−3t+4t3t=2⇒x2=2−6+32=28t=3⇒x3=2−9+108=101vavg =x3−x23−2=101−281=73cm/s

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If the particle is moving along a straight line given by the relation x = 2 - 3t +4t³ where s is in cm, and t in sec. Its average velocity during the third sec is

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80 cm/s

85 cm/s

73 cm/s

90 cm/s

answer is A.

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$\begin{array}{l} x = 2 - 3 t + 4 t^{3} \\ t = 2 \Rightarrow x_{2} = 2 - 6 + 32 = 28 \\ t = 3 \Rightarrow x_{3} = 2 - 9 + 108 = 101 \\ v_{avg} = \frac{x_{3} - x_{2}}{3 - 2} = \frac{101 - 28}{1} = 73 cm / s \end{array}$

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If the particle is moving along a straight line given by the relation x = 2 - 3t +4t3 where s is in cm, and t in sec. Its average velocity during the third sec is

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If the particle is moving along a straight line given by the relation x = 2 - 3t +4t³ where s is in cm, and t in sec. Its average velocity during the third sec is