If the perimeter of a parallelogram is 100 cm and its two adjacent sides are in the ratio 3:2, then the sides of the parallelogram measure will be:

Let ABCD be the parallelogram.

Accordingly, perimeter of the parallelogram = AB + BC + CD + DA

It is given that the perimeter of the given parallelogram is 100 cm.

∴ AB + BC + CD + DA = 100 cm

It is also given that the two adjacent sides of the parallelogram are in the ratio 3:2.

Let AB:BC = 3:2

∴AB = 3x and BC = 2x

It is known that in a parallelogram, opposite sides are equal.

∴CD = AB = 3x and DA = BC = 2x

∴ AB + BC + CD + DA = 100 cm

⇒ 3x + 2x + 3x + 2x = 100 cm

⇒ 10x = 100 cm

∴ x = 10 cm

∴CD = AB = 3x = 3 × 10 cm = 30 cm

∴ DA = BC = 2x = 2 × 10 cm = 20 cm

Thus, the sides of the parallelogram measure 30 cm, 20 cm, 30 cm, and 20 cm.