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If the perimeter of a rectangular field is 200 m and its breadth is 40 m, then find its area is (in $m^{2}$ ).

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1200

m^{2}

2400

m^{2}

4800

m^{2}

6000

m^{2}

answer is B.

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Detailed Solution

Given the perimeter of the field is 200 m and breadth is 40 m.
Perimeter of the rectangular field

= 2 (l + b)

where, l and b are the length and breadth of the rectangle.

\Rightarrow 200 = 2 (l + 40)

\Rightarrow 200 = 2 l + 80

\Rightarrow 2 l = 200 - 80

\Rightarrow 2 l = 120

\Rightarrow l = 60 m

Area of the rectangular field

= l \times b

\Rightarrow

Area

= 60 \times 40

\Rightarrow

Area

= 2400 m^{2}

So, area of rectangle is 2400

m^{2}

.
Hence, the correct option is 2.

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