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Q.

If the period of S.H.M is 6 sec and amplitude is 5 cm, the displacement at a time t=7 sec after the passage of the particle through its extreme positive displacement in ‘mm’ is

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answer is 25.

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Detailed Solution

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$X = Acos ωt = Acos \frac{2 π}{T} t = 5 \cos \frac{2 π}{6} \times 7 = 5 \cos (2 π + \frac{π}{3}) = 2 .5 cm = 25 mm$

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