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Q.

If the Planck's constant h = 6.6 × 10–34 Js, the de-Broglie’s wave length of a particle having momentum of 3.3 × 10–24 kg.ms–1 will be

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a

1×10−15 m

b

2×10−10 m

c

10−5 m

d

4×10−10 m

answer is A.

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Detailed Solution

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λ=hp=6.626×10-343.3×10-24=2×10-10 m

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