If the point A(3, 2, 2) and B(5, 5, 4) are equidistant from P, which is on x-axis, then the coordinates of Pare

The point on the x-axis is of the form P(x, 0, 0). Since, the points A and Bare equidistant from P. Therefore, 

${\mathrm{PA}}^2={\mathrm{PB}}^2$

i.e $(x-3{)}^2+(0-2{)}^2+(0-2{)}^2$ 

     $=(x-5{)}^2+(0-5{)}^2+(0-4{)}^2$

  $\Rightarrow 4x=25+25+16-17\text{ i.e., }x=\frac{49}{4}$

Thus, the point Pon the x-axis is $\left(\frac{49}{4},0,0\right)$ which is equidistant from A and B