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Q.

If the point [x1+s(x2x1),y1+s(y2y1)] divides the join of (x1,y1) and(x2,y2) internally, then

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a

s<0

b

 s>1

c

0<s<1

d

s=1

answer is B.

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Detailed Solution

P(x1+s(x2x1)),y1+s(y2y1)

P=[(1s)x1+sx21s+s,(1s)y,+sy21s+s]

 P divides A(x1,y1)&B(x2,y2) in the ratio s : 1s internally

s1s>0s(s1)>0

(s0)(s1)<0

0<s<1

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