If the points A(a, b), B(-a,-b) and P(a2, ab) are collinear then the ratio in which P divides AB¯ is

m:n=x1−x:x−x2=Aa,b B-a,-b Pa2,aba−a2:a2+a⇒1-a:1+a

If the points A(a, b), B(-a,-b) and P(a2, ab) are collinear then the ratio in which P divides AB¯ is

m:n=x1−x:x−x2=Aa,b B-a,-b Pa2,aba−a2:a2+a⇒1-a:1+a

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If the points A(a, b), B(-a,-b) and P(a², ab) are collinear then the ratio in which P divides $\bar{A B}$ is

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$1 + a : 1 - a$

1:a

1-a:1+a

a:1

answer is D.

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Detailed Solution

$m : n = x_{1} - x : x - x_{2} = A (a, b) B (- a, - b) P (a^{2}, a b)$

$a - a^{2} : a^{2} + a$ $\Rightarrow 1 - a : 1 + a$

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If the points A(a, b), B(-a,-b) and P(a2, ab) are collinear then the ratio in which P divides AB¯ is

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If the points A(a, b), B(-a,-b) and P(a², ab) are collinear then the ratio in which P divides $\bar{A B}$ is