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Q.

If the position vector of one end A of a diameter AB of the sphere  r.r-(2i-j+4k) = 5 is i+2j-k , the position vector of B is 
 

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a

3i-4j-9k

b

3i-4j+9k

c

-3i+4j-9k

d

-3i-4j+9k

answer is C.

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Detailed Solution

OA=i+2j-k Centre OC=2i-j+4k OC=OA+OB2    OB=4i-2j+8k-i-2j+k                               =3i-4j+9k

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