If the potential barrier across a p – n junction diode is 0.8 V, then the electric field intensity in the depletion region having the width of $16 \times 10^{- 6} m$ will be $x \times 10^{4} N / c$ . Then x is ____

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answer is 5.

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Detailed Solution

Electric field, $E = \frac{V}{d} = \frac{b a r r i e r p o t e n t i a l}{d i s \tan c e}$
$\Rightarrow E = \frac{0.8}{16 \times 10^{- 6}} = \frac{80}{16} \times 10^{4} = 5 \times 10^{4}$

$∴ x = 4$

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