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If the potential difference between the plates of a capacitor is increased by 20%, the energy stored in the capacitor increases by exactly

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40%

22%

44%

20%

answer is D.

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Detailed Solution

$U_{1} = \frac{1}{2} C V^{2}, U_{2} = \frac{1}{2} C {(1.2 V)}^{2} = \frac{1}{2} C V^{2} \times 1.44 ∴ \frac{U_{2} - U_{1}}{U_{1}} \times 100 = (1.44 - 1) \times 100 = 44 %$

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