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If the power of lenses L1 and L2 in a ratio of $4 : 1$ , what would be the ratio of the focal length of L1 and L2?

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4:1

1:4

2:1

1:1

answer is B.

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Detailed Solution

1:1 is the ratio of the focal length of L1 and L2 Given

p_{1} : p_{2} = 4 : 1

we know
The power of a lens is defined as the ability to converge or diverge the light rays. The power of a lens is nothing but the reciprocal of its focal length in metres.

p = \frac{1}{F (in metres)}

\frac{p_{1}}{p_{2}} = \frac{4}{1}

\Rightarrow

\frac{\frac{1}{F_{1}}}{\frac{1}{F_{2}}} = \frac{4}{1}

\Rightarrow

\frac{F_{2}}{F_{1}} = \frac{4}{1}

F_{1} : F_{2} = 1 : 4

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