If the pressure and absolute temperature of the given gas are doubled, then the new volume compared to its original volume will be

he combined gas law at two different conditions is follows below

$\frac{{\mathrm{P}}_1{\mathrm{V}}_1}{{\mathrm{T}}_1}=\frac{P_2{V}_2}{T_2} \to eqn\left(1\right)$

if ${\mathrm{P}}_1=\mathrm{P} \mathrm{then} {\mathrm{P}}_2=2\mathrm{P}$

$T_1=\mathrm{T} \mathrm{then} {\mathrm{T}}_2=2\mathrm{T}$

from equation 1

$\frac{\mathrm{P}\times {\mathrm{V}}_1}{\mathrm{T}}=\frac{2P\times V_2}{2T}$

${\mathrm{V}}_2={\mathrm{V}}_1$