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Q.

If the pressure of an ideal gas contains in a closed vessel is increased by 0.5%, the increase in temperature is 2⁰C. The initial temperature of the gas is

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a

127⁰C

b

27⁰C

c

400⁰C

d

300⁰C

answer is B.

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Detailed Solution

$As volume is constant \frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

$here T_{2} = T_{1} + 2$

$and P_{2} = \frac{100.5}{100} P_{1}$

$\frac{P_{1}}{T_{1}} = \frac{100.5 P_{1}}{100 (T_{1} + 2)}$

$solving T_{1} = 400 K$

$t_{1} = 400 - 273 = 127^{0} C$

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