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Q.

If the pressure of an ideal gas contains in a closed vessel is increased by 0.5%, the increase in temperature is 2^oC. The initial temperature of the gas is

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a

27^oC

b

127^oC

c

300^oC

d

400^oC

answer is B.

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Detailed Solution

% increase in pressure $\frac{P_{2} - P_{1}}{P_{1}} x 100 = 0.5$
T₂ - T₁ = 2^o,T₁ = ? we have $\frac{P_{2}}{P_{1}} = \frac{T_{2}}{T_{1}}$
$(\frac{P_{2}}{P_{1}} - 1) x 100 = (\frac{T_{2}}{T_{1}} - 1) x 100 \frac{1}{2} = \frac{2}{T_{1}} x 100$
T₁ = 400K = 127^o C

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