If the probability of the occurrence of a certain event $E is \frac{3}{11}$. Then the odds in favour of its occurrence is

Let there be m outcomes m favourable to E and n outcomes unfavourable to E. Then

$P\left(E\right)=\frac{m}{m+n}\Rightarrow \frac{m}{m+n}=\frac{3}{11} \left[\because P\left(E\right)=\frac{3}{11}\text{ (given) }\right]$

$\Rightarrow m=3$ and $n=8$

The odds in favour of $E=\frac{m}{n}=\frac{3}{8}$