Q.

If the product of the roots of the equation x2-3x+k=10 is -2 then the value of k is


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a

-2

b

-8

c

12 

d

8

answer is C.

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Detailed Solution

detailed_solution_thumbnail
Given quadratic equation is,
x2-3x+k=10.
The product of the roots is -2.
We know that,
The standard form of a quadratic equation is ax2+bx+c=0, where a,b  c are real numbers and a0.
And, product of the roots is given by ca.
Now,
x2-3x+k=10 x2-3x+(k-10)=0 After comparing the equation x2-3x+k-10=0 with the standard form, we get,
a=1,b=-3, c=k-10 Product of the roots =ca
-2=k-101  
k-10=-2  
k=-2+10  k=8 If the product of the roots of the equation x2-3x+k=10 is -2 then the value of k is 8.
Hence, the correct option is 3.
 
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