If the product of the roots of the equation ${\mathrm{x}}^2-3\mathrm{kx}+2{\mathrm{e}}^{2\log \mathrm{k}}-1=0$ is 17 then $\mathrm{k}=$

$\begin{array}{l}GivenEquation{x}^2-3kx+2e^{2\log k}-1=0\\ productofroots=17\\ \Rightarrow 2e^{2\log k}-1=17\\ \Rightarrow 2e^{\log k}=18\\ \Rightarrow e^{2\log k}=9\\ \Rightarrow \log k^2=\log 9\\ \Rightarrow k^2=9\\ \Rightarrow k=3\end{array}$