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Q.

If the quadratic equations  3x27x+2=0 and  kx2+7x3=0 has a common root then the positive value of k is _____

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answer is 6.

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Detailed Solution

 3x27x+12=03x26xx+2=03x(x2)1(x2)=0(3x1)(x2)=0
 x=2orx=1/3
If x=2 is a common root, then 2 lies on  
kx2+7x3=04k+143=04k+11=0

k=11/4 
If x=13 is a common root, then 13 lies on  
 kx2+7x3=0k9+733=0k+2127=0
k=6

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