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If the r. m s speed of chlorine molecule is 490 m/s at 27°C, the r.m.s speed of argon molecules at the same temperature will be (Atomic mass of argon=39.9 u, molecular mass of chlorine=70.9 u)

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451.7 m/s

551.7 m/s

651.7 m/s

751.7 m/s

answer is C.

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Detailed Solution

$v_{rms} = \sqrt{\frac{3 RT}{M}} \Rightarrow \frac{v_{1}}{v_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} \begin{array}{l} \frac{490}{v_{2}} = = \sqrt{\frac{39.9}{70.9}} = 0.75 \\ \Rightarrow v_{2} = 651.7 {ms}^{- 1} \end{array}$

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