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If the radius of 2nd Bohr orbit of hydrogen atom is r2. The radius of third Bohr orbit will be

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$\frac{9}{4} r_{2}$

4r2

$\frac{4}{9} r_{2}$

9r2

answer is C.

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Detailed Solution

$\begin{aligned} r = \frac{n^{2} h^{2}}{4 π^{2} {mZe}^{2}} \\ ∴ \frac{r_{2}}{r_{3}} = \frac{2^{2}}{3^{2}} \\ ∴ r_{3} = \frac{9}{4} r_{2} \end{aligned}$

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