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If the radius of a circle is increasing at the rate of 0.6 units/sec then the rate of change in its area when radius is 12 units

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14.4 sq.

0.1 sq.

30 sq.

0.6 sq.

answer is A.

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Detailed Solution

_{$\frac{d r}{d t} = 0.6, r = 12$}

_{$A = π r^{2}$}

_{$\frac{d A}{d t} = 2 π r . \frac{d r}{d t}$}

= _{$2 π \times 12 \times 0.6$}

= _{$14.4 π s q . u n i t s / \sec$}

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