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Q.

If the radius of a sphere is increased from $7 c m to 7.02 c m$ then find the approximate increase in the volume of the sphere.

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Detailed Solution

Given $Δ r = 0.02, r = 7$

Volume of sphere $V = \frac{4}{3} π r^{3} \Rightarrow Δ V = \frac{4}{3} π (3 r^{2}) Δ r$

$= 4 π (7)^{2} (0.02) = 28 \times 22 \times 0.02$

$Δ V = 12.32 {cm}^{3}$

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