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If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximate error in calculating its surface area

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$216 π c m^{2}$

$21.6 π c m^{2}$

$0.216 c m^{2}$

$2.16 π c m^{2}$

answer is A.

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Detailed Solution

$r = 9, δ r = 0.03$
Surface area $A = 4 π r^{2}$
$δ A = 4 π (2 r δ r) = 2.16 π c m^{2}$

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