If the radius of first Bohr orbit be $α_{o}$ , then the radius of the third orbit of hydrogen would be

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$3 α_{o}$

$6 α_{o}$

$9 α_{o}$

$\frac{1}{3} α_{o}$

answer is C.

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Detailed Solution

$Radius of orbit = \frac{α_{o} \times n^{2}}{Z} For 3^{rd} orbit n = 3 Radius of orbit = \frac{α_{o} \times 3^{2}}{1} = 9 α_{o}$

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