If the radius of the earth is suddenly halved by keeping its mass constant. Then the time period of rotation about its own axis _____ hrs.

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answer is 6.

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Detailed Solution

$Iω = const \Rightarrow \frac{2}{5} {mR}^{2} ω = const \Rightarrow T \propto R^{2}$

$\frac{R^{2}}{{(\frac{R}{2})}^{2}} = \frac{24}{T} \Rightarrow T = 6 hrs$

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