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Q.

If the rate constant k for the decomposition of hydrocarbon related with temperature is 1011⋅e−28000T, then the activation energy (Ea) is

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a

-28000 R

b

28000R

c

28000 x R

d

-28000R

answer is C.

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Detailed Solution

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Arrhenius equation:

k=Ae−EaRTk=1011⋅e−28000/T∴ −EaRT=−28000T

Ea = 28000 × R.

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