If the rate of emission of energy from a star is $2.7 \times 10^{36} J / s$ . The rate of loss of mass in the star will be

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3 ×10¹⁸ kg / s

3×10¹⁹ kg / s

3×10²⁰ kg / s

3×10²¹kg / s

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{E}{t} = (\frac{Δm}{t}) C^{2} \Rightarrow \frac{Δm}{t} = \frac{(E / t)}{C^{2}} = \frac{2 .7 \times 10^{36}}{9 \times 10^{16}} \\ = 0 .3 \times 10^{20} = 3 \times 10^{19} kg \cdot s^{- 1} \end{array}$

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