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If the rate of flux of magnetic induction through each turn of a coil of resistance R and having N turns changes from $ϕ_{1}$ to $ϕ_{2}$ then the magnitude of current that passes through the coil is

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\frac{ϕ_{2 -} ϕ_{1}}{R}

\frac{N (ϕ_{2 -} ϕ_{1})}{R}

\frac{(ϕ_{2 -} ϕ_{1})}{N R}

\frac{N R}{(ϕ_{2 -} ϕ_{1})}

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detailed solution

Correct option is B

To find the magnitude of the induced current, we can apply the equation $i = \frac{E}{R}$

here $E = N (ϕ_{2} - ϕ_{1})$

$i = \frac{N (ϕ_{2 -} ϕ_{1})}{R}$

Initial rate of flux induction = $ϕ_{1}$

Final rate of flux induction = $ϕ_{2}$

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If the rate of flux of magnetic induction through each turn of a coil of resistance R and having N turns changes from ϕ1 to ϕ2 then the magnitude of current that passes through the coil is

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If the rate of flux of magnetic induction through each turn of a coil of resistance R and having N turns changes from $ϕ_{1}$ to $ϕ_{2}$ then the magnitude of current that passes through the coil is