If the rate of polishing is ₹10/m², what is the cost of polishing a circular table top of diameter 2.6 m?

Given, Diameter of the circular table top = 2.6 m

Radius, r = $\frac{d}{2}$

r = $\frac{2.6}{2}$

r = 1.3 m

Area of the circular table top = πr²

A = 3.14 × 1.3²

A = 3.14 × 1.3 × 1.3

A = 5.3066 m²

Cost for polishing 1 m² area = ₹ 10

Cost for polishing 5.3066 m² area = ₹ 10 × 5.3066 

                                                   = ₹ 53.066